3.2340 \(\int (1-2 x)^{3/2} (3+5 x)^{3/2} \, dx\)

Optimal. Leaf size=116 \[ -\frac {1}{8} (5 x+3)^{3/2} (1-2 x)^{5/2}-\frac {11}{32} \sqrt {5 x+3} (1-2 x)^{5/2}+\frac {121}{640} \sqrt {5 x+3} (1-2 x)^{3/2}+\frac {3993 \sqrt {5 x+3} \sqrt {1-2 x}}{6400}+\frac {43923 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{6400 \sqrt {10}} \]

[Out]

-1/8*(1-2*x)^(5/2)*(3+5*x)^(3/2)+43923/64000*arcsin(1/11*22^(1/2)*(3+5*x)^(1/2))*10^(1/2)+121/640*(1-2*x)^(3/2
)*(3+5*x)^(1/2)-11/32*(1-2*x)^(5/2)*(3+5*x)^(1/2)+3993/6400*(1-2*x)^(1/2)*(3+5*x)^(1/2)

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Rubi [A]  time = 0.03, antiderivative size = 116, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 3, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {50, 54, 216} \[ -\frac {1}{8} (5 x+3)^{3/2} (1-2 x)^{5/2}-\frac {11}{32} \sqrt {5 x+3} (1-2 x)^{5/2}+\frac {121}{640} \sqrt {5 x+3} (1-2 x)^{3/2}+\frac {3993 \sqrt {5 x+3} \sqrt {1-2 x}}{6400}+\frac {43923 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{6400 \sqrt {10}} \]

Antiderivative was successfully verified.

[In]

Int[(1 - 2*x)^(3/2)*(3 + 5*x)^(3/2),x]

[Out]

(3993*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/6400 + (121*(1 - 2*x)^(3/2)*Sqrt[3 + 5*x])/640 - (11*(1 - 2*x)^(5/2)*Sqrt[3
+ 5*x])/32 - ((1 - 2*x)^(5/2)*(3 + 5*x)^(3/2))/8 + (43923*ArcSin[Sqrt[2/11]*Sqrt[3 + 5*x]])/(6400*Sqrt[10])

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 54

Int[1/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_.) + (d_.)*(x_)]), x_Symbol] :> Dist[2/Sqrt[b], Subst[Int[1/Sqrt[b*c -
a*d + d*x^2], x], x, Sqrt[a + b*x]], x] /; FreeQ[{a, b, c, d}, x] && GtQ[b*c - a*d, 0] && GtQ[b, 0]

Rule 216

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[(Rt[-b, 2]*x)/Sqrt[a]]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rubi steps

\begin {align*} \int (1-2 x)^{3/2} (3+5 x)^{3/2} \, dx &=-\frac {1}{8} (1-2 x)^{5/2} (3+5 x)^{3/2}+\frac {33}{16} \int (1-2 x)^{3/2} \sqrt {3+5 x} \, dx\\ &=-\frac {11}{32} (1-2 x)^{5/2} \sqrt {3+5 x}-\frac {1}{8} (1-2 x)^{5/2} (3+5 x)^{3/2}+\frac {121}{64} \int \frac {(1-2 x)^{3/2}}{\sqrt {3+5 x}} \, dx\\ &=\frac {121}{640} (1-2 x)^{3/2} \sqrt {3+5 x}-\frac {11}{32} (1-2 x)^{5/2} \sqrt {3+5 x}-\frac {1}{8} (1-2 x)^{5/2} (3+5 x)^{3/2}+\frac {3993 \int \frac {\sqrt {1-2 x}}{\sqrt {3+5 x}} \, dx}{1280}\\ &=\frac {3993 \sqrt {1-2 x} \sqrt {3+5 x}}{6400}+\frac {121}{640} (1-2 x)^{3/2} \sqrt {3+5 x}-\frac {11}{32} (1-2 x)^{5/2} \sqrt {3+5 x}-\frac {1}{8} (1-2 x)^{5/2} (3+5 x)^{3/2}+\frac {43923 \int \frac {1}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx}{12800}\\ &=\frac {3993 \sqrt {1-2 x} \sqrt {3+5 x}}{6400}+\frac {121}{640} (1-2 x)^{3/2} \sqrt {3+5 x}-\frac {11}{32} (1-2 x)^{5/2} \sqrt {3+5 x}-\frac {1}{8} (1-2 x)^{5/2} (3+5 x)^{3/2}+\frac {43923 \operatorname {Subst}\left (\int \frac {1}{\sqrt {11-2 x^2}} \, dx,x,\sqrt {3+5 x}\right )}{6400 \sqrt {5}}\\ &=\frac {3993 \sqrt {1-2 x} \sqrt {3+5 x}}{6400}+\frac {121}{640} (1-2 x)^{3/2} \sqrt {3+5 x}-\frac {11}{32} (1-2 x)^{5/2} \sqrt {3+5 x}-\frac {1}{8} (1-2 x)^{5/2} (3+5 x)^{3/2}+\frac {43923 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )}{6400 \sqrt {10}}\\ \end {align*}

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Mathematica [A]  time = 0.05, size = 74, normalized size = 0.64 \[ \frac {10 \sqrt {5 x+3} \left (32000 x^4-11200 x^3-26360 x^2+10774 x+603\right )+43923 \sqrt {20 x-10} \sinh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {2 x-1}\right )}{64000 \sqrt {1-2 x}} \]

Antiderivative was successfully verified.

[In]

Integrate[(1 - 2*x)^(3/2)*(3 + 5*x)^(3/2),x]

[Out]

(10*Sqrt[3 + 5*x]*(603 + 10774*x - 26360*x^2 - 11200*x^3 + 32000*x^4) + 43923*Sqrt[-10 + 20*x]*ArcSinh[Sqrt[5/
11]*Sqrt[-1 + 2*x]])/(64000*Sqrt[1 - 2*x])

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fricas [A]  time = 1.17, size = 72, normalized size = 0.62 \[ -\frac {1}{6400} \, {\left (16000 \, x^{3} + 2400 \, x^{2} - 11980 \, x - 603\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1} - \frac {43923}{128000} \, \sqrt {10} \arctan \left (\frac {\sqrt {10} {\left (20 \, x + 1\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{20 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(3/2)*(3+5*x)^(3/2),x, algorithm="fricas")

[Out]

-1/6400*(16000*x^3 + 2400*x^2 - 11980*x - 603)*sqrt(5*x + 3)*sqrt(-2*x + 1) - 43923/128000*sqrt(10)*arctan(1/2
0*sqrt(10)*(20*x + 1)*sqrt(5*x + 3)*sqrt(-2*x + 1)/(10*x^2 + x - 3))

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giac [B]  time = 1.03, size = 203, normalized size = 1.75 \[ -\frac {1}{192000} \, \sqrt {5} {\left (2 \, {\left (4 \, {\left (8 \, {\left (60 \, x - 119\right )} {\left (5 \, x + 3\right )} + 6163\right )} {\left (5 \, x + 3\right )} - 66189\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} - 184305 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right )\right )} - \frac {7}{24000} \, \sqrt {5} {\left (2 \, {\left (4 \, {\left (40 \, x - 59\right )} {\left (5 \, x + 3\right )} + 1293\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} + 4785 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right )\right )} + \frac {3}{500} \, \sqrt {5} {\left (2 \, {\left (20 \, x - 23\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} - 143 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right )\right )} + \frac {9}{50} \, \sqrt {5} {\left (11 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right ) + 2 \, \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(3/2)*(3+5*x)^(3/2),x, algorithm="giac")

[Out]

-1/192000*sqrt(5)*(2*(4*(8*(60*x - 119)*(5*x + 3) + 6163)*(5*x + 3) - 66189)*sqrt(5*x + 3)*sqrt(-10*x + 5) - 1
84305*sqrt(2)*arcsin(1/11*sqrt(22)*sqrt(5*x + 3))) - 7/24000*sqrt(5)*(2*(4*(40*x - 59)*(5*x + 3) + 1293)*sqrt(
5*x + 3)*sqrt(-10*x + 5) + 4785*sqrt(2)*arcsin(1/11*sqrt(22)*sqrt(5*x + 3))) + 3/500*sqrt(5)*(2*(20*x - 23)*sq
rt(5*x + 3)*sqrt(-10*x + 5) - 143*sqrt(2)*arcsin(1/11*sqrt(22)*sqrt(5*x + 3))) + 9/50*sqrt(5)*(11*sqrt(2)*arcs
in(1/11*sqrt(22)*sqrt(5*x + 3)) + 2*sqrt(5*x + 3)*sqrt(-10*x + 5))

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maple [A]  time = 0.00, size = 104, normalized size = 0.90 \[ \frac {43923 \sqrt {\left (-2 x +1\right ) \left (5 x +3\right )}\, \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )}{128000 \sqrt {5 x +3}\, \sqrt {-2 x +1}}+\frac {\left (-2 x +1\right )^{\frac {3}{2}} \left (5 x +3\right )^{\frac {5}{2}}}{20}+\frac {11 \left (5 x +3\right )^{\frac {5}{2}} \sqrt {-2 x +1}}{200}-\frac {121 \left (5 x +3\right )^{\frac {3}{2}} \sqrt {-2 x +1}}{1600}-\frac {3993 \sqrt {-2 x +1}\, \sqrt {5 x +3}}{6400} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((-2*x+1)^(3/2)*(5*x+3)^(3/2),x)

[Out]

1/20*(-2*x+1)^(3/2)*(5*x+3)^(5/2)+11/200*(5*x+3)^(5/2)*(-2*x+1)^(1/2)-121/1600*(5*x+3)^(3/2)*(-2*x+1)^(1/2)-39
93/6400*(-2*x+1)^(1/2)*(5*x+3)^(1/2)+43923/128000*((-2*x+1)*(5*x+3))^(1/2)/(5*x+3)^(1/2)/(-2*x+1)^(1/2)*10^(1/
2)*arcsin(20/11*x+1/11)

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maxima [A]  time = 1.23, size = 70, normalized size = 0.60 \[ \frac {1}{4} \, {\left (-10 \, x^{2} - x + 3\right )}^{\frac {3}{2}} x + \frac {1}{80} \, {\left (-10 \, x^{2} - x + 3\right )}^{\frac {3}{2}} + \frac {363}{320} \, \sqrt {-10 \, x^{2} - x + 3} x - \frac {43923}{128000} \, \sqrt {10} \arcsin \left (-\frac {20}{11} \, x - \frac {1}{11}\right ) + \frac {363}{6400} \, \sqrt {-10 \, x^{2} - x + 3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(3/2)*(3+5*x)^(3/2),x, algorithm="maxima")

[Out]

1/4*(-10*x^2 - x + 3)^(3/2)*x + 1/80*(-10*x^2 - x + 3)^(3/2) + 363/320*sqrt(-10*x^2 - x + 3)*x - 43923/128000*
sqrt(10)*arcsin(-20/11*x - 1/11) + 363/6400*sqrt(-10*x^2 - x + 3)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int {\left (1-2\,x\right )}^{3/2}\,{\left (5\,x+3\right )}^{3/2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1 - 2*x)^(3/2)*(5*x + 3)^(3/2),x)

[Out]

int((1 - 2*x)^(3/2)*(5*x + 3)^(3/2), x)

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sympy [A]  time = 7.90, size = 269, normalized size = 2.32 \[ \begin {cases} - \frac {25 i \left (x + \frac {3}{5}\right )^{\frac {9}{2}}}{\sqrt {10 x - 5}} + \frac {275 i \left (x + \frac {3}{5}\right )^{\frac {7}{2}}}{4 \sqrt {10 x - 5}} - \frac {1573 i \left (x + \frac {3}{5}\right )^{\frac {5}{2}}}{32 \sqrt {10 x - 5}} - \frac {1331 i \left (x + \frac {3}{5}\right )^{\frac {3}{2}}}{640 \sqrt {10 x - 5}} + \frac {43923 i \sqrt {x + \frac {3}{5}}}{6400 \sqrt {10 x - 5}} - \frac {43923 \sqrt {10} i \operatorname {acosh}{\left (\frac {\sqrt {110} \sqrt {x + \frac {3}{5}}}{11} \right )}}{64000} & \text {for}\: \frac {10 \left |{x + \frac {3}{5}}\right |}{11} > 1 \\\frac {43923 \sqrt {10} \operatorname {asin}{\left (\frac {\sqrt {110} \sqrt {x + \frac {3}{5}}}{11} \right )}}{64000} + \frac {25 \left (x + \frac {3}{5}\right )^{\frac {9}{2}}}{\sqrt {5 - 10 x}} - \frac {275 \left (x + \frac {3}{5}\right )^{\frac {7}{2}}}{4 \sqrt {5 - 10 x}} + \frac {1573 \left (x + \frac {3}{5}\right )^{\frac {5}{2}}}{32 \sqrt {5 - 10 x}} + \frac {1331 \left (x + \frac {3}{5}\right )^{\frac {3}{2}}}{640 \sqrt {5 - 10 x}} - \frac {43923 \sqrt {x + \frac {3}{5}}}{6400 \sqrt {5 - 10 x}} & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)**(3/2)*(3+5*x)**(3/2),x)

[Out]

Piecewise((-25*I*(x + 3/5)**(9/2)/sqrt(10*x - 5) + 275*I*(x + 3/5)**(7/2)/(4*sqrt(10*x - 5)) - 1573*I*(x + 3/5
)**(5/2)/(32*sqrt(10*x - 5)) - 1331*I*(x + 3/5)**(3/2)/(640*sqrt(10*x - 5)) + 43923*I*sqrt(x + 3/5)/(6400*sqrt
(10*x - 5)) - 43923*sqrt(10)*I*acosh(sqrt(110)*sqrt(x + 3/5)/11)/64000, 10*Abs(x + 3/5)/11 > 1), (43923*sqrt(1
0)*asin(sqrt(110)*sqrt(x + 3/5)/11)/64000 + 25*(x + 3/5)**(9/2)/sqrt(5 - 10*x) - 275*(x + 3/5)**(7/2)/(4*sqrt(
5 - 10*x)) + 1573*(x + 3/5)**(5/2)/(32*sqrt(5 - 10*x)) + 1331*(x + 3/5)**(3/2)/(640*sqrt(5 - 10*x)) - 43923*sq
rt(x + 3/5)/(6400*sqrt(5 - 10*x)), True))

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